From 0db3dc75f30239aa3b36071c7b9ff21c16ba449a Mon Sep 17 00:00:00 2001 From: =?UTF-8?q?Ren=C3=A9=20Scharfe?= Date: Fri, 25 Aug 2017 21:06:28 +0200 Subject: apply: remove epoch date from regex We check the date of epoch timestamp candidates already with starts_with(). Move beyond that part using skip_prefix() instead of checking it again using a regular expression. Also group the minutes part, so that we can access them using a substring match instead of using a magic number. Signed-off-by: Rene Scharfe Signed-off-by: Junio C Hamano diff --git a/apply.c b/apply.c index e5d7959..3997f73 100644 --- a/apply.c +++ b/apply.c @@ -812,9 +812,7 @@ static int has_epoch_timestamp(const char *nameline) * 1970-01-01, and the seconds part must be "00". */ const char stamp_regexp[] = - "^(1969-12-31|1970-01-01)" - " " - "[0-2][0-9]:[0-5][0-9]:00(\\.0+)?" + "^[0-2][0-9]:([0-5][0-9]):00(\\.0+)?" " " "([-+][0-2][0-9]:?[0-5][0-9])\n"; const char *timestamp = NULL, *cp, *colon; @@ -834,9 +832,9 @@ static int has_epoch_timestamp(const char *nameline) * YYYY-MM-DD hh:mm:ss must be from either 1969-12-31 * (west of GMT) or 1970-01-01 (east of GMT) */ - if (starts_with(timestamp, "1969-12-31")) + if (skip_prefix(timestamp, "1969-12-31 ", ×tamp)) epoch_hour = 24; - else if (starts_with(timestamp, "1970-01-01")) + else if (skip_prefix(timestamp, "1970-01-01 ", ×tamp)) epoch_hour = 0; else return 0; @@ -858,8 +856,8 @@ static int has_epoch_timestamp(const char *nameline) return 0; } - hour = strtol(timestamp + 11, NULL, 10); - minute = strtol(timestamp + 14, NULL, 10); + hour = strtol(timestamp, NULL, 10); + minute = strtol(timestamp + m[1].rm_so, NULL, 10); zoneoffset = strtol(timestamp + m[3].rm_so + 1, (char **) &colon, 10); if (*colon == ':') -- cgit v0.10.2-6-g49f6