From c3ff8f6c145638afe996b51e91375fd94cd064d0 Mon Sep 17 00:00:00 2001
From: =?UTF-8?q?Ren=C3=A9=20Scharfe?= <l.s.r@web.de>
Date: Thu, 7 Dec 2017 21:51:26 +0100
Subject: strbuf: release memory on read error in strbuf_read_once()

If other strbuf add functions cause the first allocation and
subsequently encounter an error then they release the memory, restoring
the pristine state of the strbuf.  That simplifies error handling for
callers.

Do the same in strbuf_read_once(), and do it also in case no bytes were
read -- which may or may not be an error as well, depending on the
caller.

Signed-off-by: Rene Scharfe <l.s.r@web.de>
Signed-off-by: Junio C Hamano <gitster@pobox.com>

diff --git a/strbuf.c b/strbuf.c
index ace58e7..0809bca 100644
--- a/strbuf.c
+++ b/strbuf.c
@@ -393,12 +393,15 @@ ssize_t strbuf_read(struct strbuf *sb, int fd, size_t hint)
 
 ssize_t strbuf_read_once(struct strbuf *sb, int fd, size_t hint)
 {
+	size_t oldalloc = sb->alloc;
 	ssize_t cnt;
 
 	strbuf_grow(sb, hint ? hint : 8192);
 	cnt = xread(fd, sb->buf + sb->len, sb->alloc - sb->len - 1);
 	if (cnt > 0)
 		strbuf_setlen(sb, sb->len + cnt);
+	else if (oldalloc == 0)
+		strbuf_release(sb);
 	return cnt;
 }
 
-- 
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