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-rw-r--r--builtin/diff.c37
1 files changed, 18 insertions, 19 deletions
diff --git a/builtin/diff.c b/builtin/diff.c
index abdd613..661fdde 100644
--- a/builtin/diff.c
+++ b/builtin/diff.c
@@ -253,8 +253,8 @@ int cmd_diff(int argc, const char **argv, const char *prefix)
{
int i;
struct rev_info rev;
- struct object_array_entry ent[100];
- int ents = 0, blobs = 0, paths = 0;
+ struct object_array ent = OBJECT_ARRAY_INIT;
+ int blobs = 0, paths = 0;
const char *path = NULL;
struct blobinfo blob[2];
int nongit;
@@ -351,13 +351,8 @@ int cmd_diff(int argc, const char **argv, const char *prefix)
if (obj->type == OBJ_COMMIT)
obj = &((struct commit *)obj)->tree->object;
if (obj->type == OBJ_TREE) {
- if (ARRAY_SIZE(ent) <= ents)
- die(_("more than %d trees given: '%s'"),
- (int) ARRAY_SIZE(ent), name);
obj->flags |= flags;
- ent[ents].item = obj;
- ent[ents].name = name;
- ents++;
+ add_object_array(obj, name, &ent);
continue;
}
if (obj->type == OBJ_BLOB) {
@@ -381,7 +376,7 @@ int cmd_diff(int argc, const char **argv, const char *prefix)
/*
* Now, do the arguments look reasonable?
*/
- if (!ents) {
+ if (!ent.nr) {
switch (blobs) {
case 0:
result = builtin_diff_files(&rev, argc, argv);
@@ -402,22 +397,26 @@ int cmd_diff(int argc, const char **argv, const char *prefix)
}
else if (blobs)
usage(builtin_diff_usage);
- else if (ents == 1)
+ else if (ent.nr == 1)
result = builtin_diff_index(&rev, argc, argv);
- else if (ents == 2)
- result = builtin_diff_tree(&rev, argc, argv, &ent[0], &ent[1]);
- else if (ent[0].item->flags & UNINTERESTING) {
+ else if (ent.nr == 2)
+ result = builtin_diff_tree(&rev, argc, argv,
+ &ent.objects[0], &ent.objects[1]);
+ else if (ent.objects[0].item->flags & UNINTERESTING) {
/*
* diff A...B where there is at least one merge base
- * between A and B. We have ent[0] == merge-base,
- * ent[ents-2] == A, and ent[ents-1] == B. Show diff
- * between the base and B. Note that we pick one
- * merge base at random if there are more than one.
+ * between A and B. We have ent.objects[0] ==
+ * merge-base, ent.objects[ents-2] == A, and
+ * ent.objects[ents-1] == B. Show diff between the
+ * base and B. Note that we pick one merge base at
+ * random if there are more than one.
*/
- result = builtin_diff_tree(&rev, argc, argv, &ent[0], &ent[ents-1]);
+ result = builtin_diff_tree(&rev, argc, argv,
+ &ent.objects[0],
+ &ent.objects[ent.nr-1]);
} else
result = builtin_diff_combined(&rev, argc, argv,
- ent, ents);
+ ent.objects, ent.nr);
result = diff_result_code(&rev.diffopt, result);
if (1 < rev.diffopt.skip_stat_unmatch)
refresh_index_quietly();