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authorDenton Liu <liu.denton@gmail.com>2019-04-29 08:28:20 (GMT)
committerJunio C Hamano <gitster@pobox.com>2019-05-05 06:20:08 (GMT)
commitb199d7147a218c3b10b077f9caad0f207bc34d7a (patch)
tree56c58e8053c5f5c8d177d84f1f29ca7449c17d42 /quote.h
parent554544276a604c144df45efcb060c80aa322088c (diff)
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*.[ch]: remove extern from function declarations using sed
There has been a push to remove extern from function declarations. Finish the job by removing all instances of "extern" for function declarations in headers using sed. This was done by running the following on my system with sed 4.2.2: $ git ls-files \*.{c,h} | grep -v ^compat/ | xargs sed -i'' -e 's/^\(\s*\)extern \([^(]*([^*]\)/\1\2/' Files under `compat/` are intentionally excluded as some are directly copied from external sources and we should avoid churning them as much as possible. Then, leftover instances of extern were found by running $ git grep -w -C3 extern \*.{c,h} and manually checking the output. No other instances were found. Note that the regex used specifically excludes function variables which _should_ be left as extern. Not the most elegant way to do it but it gets the job done. Signed-off-by: Denton Liu <liu.denton@gmail.com> Signed-off-by: Junio C Hamano <gitster@pobox.com>
Diffstat (limited to 'quote.h')
-rw-r--r--quote.h2
1 files changed, 1 insertions, 1 deletions
diff --git a/quote.h b/quote.h
index 89f99e9..86c0d94 100644
--- a/quote.h
+++ b/quote.h
@@ -31,7 +31,7 @@ struct strbuf;
void sq_quote_buf(struct strbuf *, const char *src);
void sq_quote_argv(struct strbuf *, const char **argv);
-extern void sq_quotef(struct strbuf *, const char *fmt, ...);
+void sq_quotef(struct strbuf *, const char *fmt, ...);
/*
* These match their non-pretty variants, except that they avoid