parse_options: allocate a new array when concatenating

In exactly one callers (builtin/revert.c), we build up the
options list dynamically from multiple arrays. We do so by
manually inserting "filler" entries into one array, and then
copying the other array into the allocated space.

This is tedious and error-prone, as you have to adjust the
filler any time the second array is modified (although we do
at least check and die() when the counts do not match up).

Instead, let's just allocate a new array.

Signed-off-by: Jeff King <peff@peff.net>
Signed-off-by: Junio C Hamano <gitster@pobox.com>

1 files changed, 17 insertions, 12 deletions

diff --git a/parse-options-cb.c b/parse-options-cb.c
index 239898d..2d87520 100644
--- a/parse-options-cb.c
+++ b/parse-options-cb.c
@@ -117,19 +117,24 @@ int parse_opt_tertiary(const struct option *opt, const char *arg, int unset)
 	return 0;
 }
 
-int parse_options_concat(struct option *dst, size_t dst_size, struct option *src)
+struct option *parse_options_concat(struct option *a, struct option *b)
 {
-	int i, j;
-
-	for (i = 0; i < dst_size; i++)
-		if (dst[i].type == OPTION_END)
-			break;
-	for (j = 0; i < dst_size; i++, j++) {
-		dst[i] = src[j];
-		if (src[j].type == OPTION_END)
-			return 0;
-	}
-	return -1;
+	struct option *ret;
+	size_t i, a_len = 0, b_len = 0;
+
+	for (i = 0; a[i].type != OPTION_END; i++)
+		a_len++;
+	for (i = 0; b[i].type != OPTION_END; i++)
+		b_len++;
+
+	ALLOC_ARRAY(ret, st_add3(a_len, b_len, 1));
+	for (i = 0; i < a_len; i++)
+		ret[i] = a[i];
+	for (i = 0; i < b_len; i++)
+		ret[a_len + i] = b[i];
+	ret[a_len + b_len] = b[b_len]; /* final OPTION_END */
+
+	return ret;
 }
 
 int parse_opt_string_list(const struct option *opt, const char *arg, int unset)